Solve for h 3.5=- log of h

$3.5 = - \log (h)$

Rewrite the equation as $- \log (h) = 3.5$ .

$- \log (h) = 3.5$

Divide each term in $- \log (h) = 3.5$ by $- 1$ and simplify.

Divide each term in $- \log (h) = 3.5$ by $- 1$ .

$\frac{- \log (h)}{- 1} = \frac{3.5}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{\log (h)}{1} = \frac{3.5}{- 1}$

Divide $\log (h)$ by $1$ .

$\log (h) = \frac{3.5}{- 1}$

Simplify the right side.

Divide $3.5$ by $- 1$ .

$\log (h) = - 3.5$

Rewrite $\log (h) = - 3.5$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$10^{- 3.5} = h$

Solve for $h$ .

Rewrite the equation as $h = 10^{- 3.5}$ .

$h = 10^{- 3.5}$

Simplify $10^{- 3.5}$ .

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$h = \frac{1}{10^{3.5}}$

Raise $10$ to the power of $3.5$ .

$h = \frac{1}{3162.27766016}$

Divide $1$ by $3162.27766016$ .

$h = 0.00031622$

Solve for h 3.5=- log of h

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