Solve for h 3(h-2)+1=h+4+2h

$3 (h - 2) + 1 = h + 4 + 2 h$

Step 1

Since $h$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$h + 4 + 2 h = 3 (h - 2) + 1$

Step 2

Add $h$ and $2 h$ .

$3 h + 4 = 3 (h - 2) + 1$

Step 3

Simplify $3 (h - 2) + 1$ .

Simplify each term.

Apply the distributive property.

$3 h + 4 = 3 h + 3 \cdot - 2 + 1$

Multiply $3$ by $- 2$ .

$3 h + 4 = 3 h - 6 + 1$

Add $- 6$ and $1$ .

$3 h + 4 = 3 h - 5$

Step 4

Move all terms containing $h$ to the left side of the equation.

Subtract $3 h$ from both sides of the equation.

$3 h + 4 - 3 h = - 5$

Combine the opposite terms in $3 h + 4 - 3 h$ .

Subtract $3 h$ from $3 h$ .

$0 + 4 = - 5$

Add $0$ and $4$ .

$4 = - 5$

Step 5

Since $4 \neq - 5$ , there are no solutions.

No solution