Solve for h 3(h-4)=-1/2(24-6h)

$3 (h - 4) = - \frac{1}{2} (24 - 6 h)$

Step 1

Simplify $3 (h - 4)$ .

Start simplifying.

$0 + 0 + 3 (h - 4) = - \frac{1}{2} \cdot (24 - 6 h)$

Simplify by adding zeros.

$3 (h - 4) = - \frac{1}{2} \cdot (24 - 6 h)$

Apply the distributive property.

$3 h + 3 \cdot - 4 = - \frac{1}{2} \cdot (24 - 6 h)$

Multiply $3$ by $- 4$ .

$3 h - 12 = - \frac{1}{2} \cdot (24 - 6 h)$

Step 2

Simplify $- \frac{1}{2} \cdot (24 - 6 h)$ .

Apply the distributive property.

$3 h - 12 = - \frac{1}{2} \cdot 24 - \frac{1}{2} (- 6 h)$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{1}{2}$ into the numerator.

$3 h - 12 = \frac{- 1}{2} \cdot 24 - \frac{1}{2} (- 6 h)$

Factor $2$ out of $24$ .

$3 h - 12 = \frac{- 1}{2} \cdot (2 (12)) - \frac{1}{2} (- 6 h)$

Cancel the common factor.

$3 h - 12 = \frac{- 1}{2} \cdot (2 \cdot 12) - \frac{1}{2} (- 6 h)$

Rewrite the expression.

$3 h - 12 = - 1 \cdot 12 - \frac{1}{2} (- 6 h)$

Multiply $- 1$ by $12$ .

$3 h - 12 = - 12 - \frac{1}{2} (- 6 h)$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{1}{2}$ into the numerator.

$3 h - 12 = - 12 + \frac{- 1}{2} (- 6 h)$

Factor $2$ out of $- 6 h$ .

$3 h - 12 = - 12 + \frac{- 1}{2} (2 (- 3 h))$

Cancel the common factor.

$3 h - 12 = - 12 + \frac{- 1}{2} (2 (- 3 h))$

Rewrite the expression.

$3 h - 12 = - 12 - 1 (- 3 h)$

Multiply $- 3$ by $- 1$ .

$3 h - 12 = - 12 + 3 h$

Step 3

Move all terms containing $h$ to the left side of the equation.

Subtract $3 h$ from both sides of the equation.

$3 h - 12 - 3 h = - 12$

Combine the opposite terms in $3 h - 12 - 3 h$ .

Subtract $3 h$ from $3 h$ .

$0 - 12 = - 12$

Subtract $12$ from $0$ .

$- 12 = - 12$

Step 4

Since $- 12 = - 12$ , the equation will always be true for any value of $h$ .

All real numbers

Step 5

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$

Solve for h 3(h-4)=-1/2(24-6h)

Related Questions

Support LCMGCF.com by disabling your adblocker.