Solve for h 3h-2(4h-5)=10-5h

$3 h - 2 (4 h - 5) = 10 - 5 h$

Simplify $3 h - 2 (4 h - 5)$ .

Simplify each term.

Apply the distributive property.

$3 h - 2 (4 h) - 2 \cdot - 5 = 10 - 5 h$

Multiply $4$ by $- 2$ .

$3 h - 8 h - 2 \cdot - 5 = 10 - 5 h$

Multiply $- 2$ by $- 5$ .

$3 h - 8 h + 10 = 10 - 5 h$

Subtract $8 h$ from $3 h$ .

$- 5 h + 10 = 10 - 5 h$

Move all terms containing $h$ to the left side of the equation.

Add $5 h$ to both sides of the equation.

$- 5 h + 10 + 5 h = 10$

Combine the opposite terms in $- 5 h + 10 + 5 h$ .

Add $- 5 h$ and $5 h$ .

$0 + 10 = 10$

Add $0$ and $10$ .

$10 = 10$

Since $10 = 10$ , the equation will always be true for any value of $h$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$