Solve for h 3h+7>=-h-10

$3 h + 7 \geq - h - 10$

Step 1

Move all terms containing $h$ to the left side of the inequality.

Add $h$ to both sides of the inequality.

$3 h + 7 + h \geq - 10$

Add $3 h$ and $h$ .

$4 h + 7 \geq - 10$

Step 2

Move all terms not containing $h$ to the right side of the inequality.

Subtract $7$ from both sides of the inequality.

$4 h \geq - 10 - 7$

Subtract $7$ from $- 10$ .

$4 h \geq - 17$

Step 3

Divide each term in $4 h \geq - 17$ by $4$ and simplify.

Divide each term in $4 h \geq - 17$ by $4$ .

$\frac{4 h}{4} \geq \frac{- 17}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 h}{4} \geq \frac{- 17}{4}$

Divide $h$ by $1$ .

$h \geq \frac{- 17}{4}$

Simplify the right side.

Move the negative in front of the fraction.

$h \geq - \frac{17}{4}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$h \geq - \frac{17}{4}$

Interval Notation:

$[- \frac{17}{4}, \infty)$