Solve for h 3h+9>15

$3 h + 9 > 15$

Step 1

Move all terms not containing $h$ to the right side of the inequality.

Subtract $9$ from both sides of the inequality.

$3 h > 15 - 9$

Subtract $9$ from $15$ .

$3 h > 6$

Step 2

Divide each term in $3 h > 6$ by $3$ and simplify.

Divide each term in $3 h > 6$ by $3$ .

$\frac{3 h}{3} > \frac{6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 h}{3} > \frac{6}{3}$

Divide $h$ by $1$ .

$h > \frac{6}{3}$

Simplify the right side.

Divide $6$ by $3$ .

$h > 2$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$h > 2$

Interval Notation:

$(2, \infty)$