Solve for h -4(-5h-4)=2(10h+8)

$- 4 (- 5 h - 4) = 2 (10 h + 8)$

Simplify $- 4 (- 5 h - 4)$ .

Start simplifying.

$0 + 0 - 4 (- 5 h - 4) = 2 (10 h + 8)$

Simplify by adding zeros.

$- 4 (- 5 h - 4) = 2 (10 h + 8)$

Apply the distributive property.

$- 4 (- 5 h) - 4 \cdot - 4 = 2 (10 h + 8)$

Multiply.

Multiply $- 5$ by $- 4$ .

$20 h - 4 \cdot - 4 = 2 (10 h + 8)$

Multiply $- 4$ by $- 4$ .

$20 h + 16 = 2 (10 h + 8)$

Simplify $2 (10 h + 8)$ .

Apply the distributive property.

$20 h + 16 = 2 (10 h) + 2 \cdot 8$

Multiply.

Multiply $10$ by $2$ .

$20 h + 16 = 20 h + 2 \cdot 8$

Multiply $2$ by $8$ .

$20 h + 16 = 20 h + 16$

Move all terms containing $h$ to the left side of the equation.

Subtract $20 h$ from both sides of the equation.

$20 h + 16 - 20 h = 16$

Combine the opposite terms in $20 h + 16 - 20 h$ .

Subtract $20 h$ from $20 h$ .

$0 + 16 = 16$

Add $0$ and $16$ .

$16 = 16$

Since $16 = 16$ , the equation will always be true for any value of $h$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$