Solve for h 5(1+4h)+2h=27

$5 (1 + 4 h) + 2 h = 27$

Step 1

Simplify $5 (1 + 4 h) + 2 h$ .

Simplify each term.

Apply the distributive property.

$5 \cdot 1 + 5 (4 h) + 2 h = 27$

Multiply $5$ by $1$ .

$5 + 5 (4 h) + 2 h = 27$

Multiply $4$ by $5$ .

$5 + 20 h + 2 h = 27$

Add $20 h$ and $2 h$ .

$5 + 22 h = 27$

Step 2

Move all terms not containing $h$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$22 h = 27 - 5$

Subtract $5$ from $27$ .

$22 h = 22$

Step 3

Divide each term in $22 h = 22$ by $22$ and simplify.

Divide each term in $22 h = 22$ by $22$ .

$\frac{22 h}{22} = \frac{22}{22}$

Simplify the left side.

Cancel the common factor of $22$ .

Cancel the common factor.

$\frac{22 h}{22} = \frac{22}{22}$

Divide $h$ by $1$ .

$h = \frac{22}{22}$

Simplify the right side.

Divide $22$ by $22$ .

$h = 1$