Solve for h -5(h+12)-(4h-2)=h-8

$- 5 (h + 12) - (4 h - 2) = h - 8$

Step 1

Simplify $- 5 (h + 12) - (4 h - 2)$ .

Simplify each term.

Apply the distributive property.

$- 5 h - 5 \cdot 12 - (4 h - 2) = h - 8$

Multiply $- 5$ by $12$ .

$- 5 h - 60 - (4 h - 2) = h - 8$

Apply the distributive property.

$- 5 h - 60 - (4 h) - - 2 = h - 8$

Multiply $4$ by $- 1$ .

$- 5 h - 60 - 4 h - - 2 = h - 8$

Multiply $- 1$ by $- 2$ .

$- 5 h - 60 - 4 h + 2 = h - 8$

Simplify by adding terms.

Subtract $4 h$ from $- 5 h$ .

$- 9 h - 60 + 2 = h - 8$

Add $- 60$ and $2$ .

$- 9 h - 58 = h - 8$

Step 2

Move all terms containing $h$ to the left side of the equation.

Subtract $h$ from both sides of the equation.

$- 9 h - 58 - h = - 8$

Subtract $h$ from $- 9 h$ .

$- 10 h - 58 = - 8$

Step 3

Move all terms not containing $h$ to the right side of the equation.

Add $58$ to both sides of the equation.

$- 10 h = - 8 + 58$

Add $- 8$ and $58$ .

$- 10 h = 50$

Step 4

Divide each term in $- 10 h = 50$ by $- 10$ and simplify.

Divide each term in $- 10 h = 50$ by $- 10$ .

$\frac{- 10 h}{- 10} = \frac{50}{- 10}$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 h}{- 10} = \frac{50}{- 10}$

Divide $h$ by $1$ .

$h = \frac{50}{- 10}$

Simplify the right side.

Divide $50$ by $- 10$ .

$h = - 5$