Solve for h 8+h>2+3h

$8 + h > 2 + 3 h$

Move all terms containing $h$ to the left side of the inequality.

Subtract $3 h$ from both sides of the inequality.

$8 + h - 3 h > 2$

Subtract $3 h$ from $h$ .

$8 - 2 h > 2$

Move all terms not containing $h$ to the right side of the inequality.

Subtract $8$ from both sides of the inequality.

$- 2 h > 2 - 8$

Subtract $8$ from $2$ .

$- 2 h > - 6$

Divide each term in $- 2 h > - 6$ by $- 2$ and simplify.

Divide each term in $- 2 h > - 6$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 h}{- 2} < \frac{- 6}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 h}{- 2} < \frac{- 6}{- 2}$

Divide $h$ by $1$ .

$h < \frac{- 6}{- 2}$

Simplify the right side.

Divide $- 6$ by $- 2$ .

$h < 3$

The result can be shown in multiple forms.

Inequality Form:

$h < 3$

Interval Notation:

$(- \infty, 3)$

Solve for h 8+h>2+3h

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