Solve for h -8(-h-3)=-16h

$- 8 (- h - 3) = - 16 h$

Step 1

Simplify $- 8 (- h - 3)$ .

Start simplifying.

$0 + 0 - 8 (- h - 3) = - 16 h$

Simplify by adding zeros.

$- 8 (- h - 3) = - 16 h$

Apply the distributive property.

$- 8 (- h) - 8 \cdot - 3 = - 16 h$

Multiply.

Multiply $- 1$ by $- 8$ .

$8 h - 8 \cdot - 3 = - 16 h$

Multiply $- 8$ by $- 3$ .

$8 h + 24 = - 16 h$

Step 2

Move all terms containing $h$ to the left side of the equation.

Add $16 h$ to both sides of the equation.

$8 h + 24 + 16 h = 0$

Add $8 h$ and $16 h$ .

$24 h + 24 = 0$

Step 3

Subtract $24$ from both sides of the equation.

$24 h = - 24$

Step 4

Divide each term in $24 h = - 24$ by $24$ and simplify.

Divide each term in $24 h = - 24$ by $24$ .

$\frac{24 h}{24} = \frac{- 24}{24}$

Simplify the left side.

Cancel the common factor of $24$ .

Cancel the common factor.

$\frac{24 h}{24} = \frac{- 24}{24}$

Divide $h$ by $1$ .

$h = \frac{- 24}{24}$

Simplify the right side.

Divide $- 24$ by $24$ .

$h = - 1$