Solve for h -9+3h=2h+7-h

$- 9 + 3 h = 2 h + 7 - h$

Step 1

Since $h$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$2 h + 7 - h = - 9 + 3 h$

Step 2

Subtract $h$ from $2 h$ .

$h + 7 = - 9 + 3 h$

Step 3

Move all terms containing $h$ to the left side of the equation.

Subtract $3 h$ from both sides of the equation.

$h + 7 - 3 h = - 9$

Subtract $3 h$ from $h$ .

$- 2 h + 7 = - 9$

Step 4

Move all terms not containing $h$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- 2 h = - 9 - 7$

Subtract $7$ from $- 9$ .

$- 2 h = - 16$

Step 5

Divide each term in $- 2 h = - 16$ by $- 2$ and simplify.

Divide each term in $- 2 h = - 16$ by $- 2$ .

$\frac{- 2 h}{- 2} = \frac{- 16}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 h}{- 2} = \frac{- 16}{- 2}$

Divide $h$ by $1$ .

$h = \frac{- 16}{- 2}$

Simplify the right side.

Divide $- 16$ by $- 2$ .

$h = 8$