Solve for h 9h-2<=10h-5

$9 h - 2 \leq 10 h - 5$

Move all terms containing $h$ to the left side of the inequality.

Subtract $10 h$ from both sides of the inequality.

$9 h - 2 - 10 h \leq - 5$

Subtract $10 h$ from $9 h$ .

$- h - 2 \leq - 5$

Move all terms not containing $h$ to the right side of the inequality.

Add $2$ to both sides of the inequality.

$- h \leq - 5 + 2$

Add $- 5$ and $2$ .

$- h \leq - 3$

Divide each term in $- h \leq - 3$ by $- 1$ and simplify.

Divide each term in $- h \leq - 3$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- h}{- 1} \geq \frac{- 3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{h}{1} \geq \frac{- 3}{- 1}$

Divide $h$ by $1$ .

$h \geq \frac{- 3}{- 1}$

Simplify the right side.

Divide $- 3$ by $- 1$ .

$h \geq 3$

The result can be shown in multiple forms.

Inequality Form:

$h \geq 3$

Interval Notation:

$[3, \infty)$

Solve for h 9h-2<=10h-5

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