Solve for h a=1/2*(h(b+c))

$a = \frac{1}{2} \cdot (h (b + c))$

Step 1

Rewrite the equation as $\frac{1}{2} \cdot (h (b + c)) = a$ .

$\frac{1}{2} \cdot (h (b + c)) = a$

Step 2

Multiply both sides of the equation by $2$ .

$2 (\frac{1}{2} \cdot (h (b + c))) = 2 a$

Step 3

Simplify the left side.

Simplify $2 (\frac{1}{2} \cdot (h (b + c)))$ .

Apply the distributive property.

$2 (\frac{1}{2} \cdot (h b + h c)) = 2 a$

Apply the distributive property.

$2 (\frac{1}{2} (h b) + \frac{1}{2} (h c)) = 2 a$

Multiply $\frac{1}{2} (h b)$ .

Combine $h$ and $\frac{1}{2}$ .

$2 (\frac{h}{2} b + \frac{1}{2} (h c)) = 2 a$

Combine $\frac{h}{2}$ and $b$ .

$2 (\frac{h b}{2} + \frac{1}{2} (h c)) = 2 a$

Multiply $\frac{1}{2} (h c)$ .

Combine $h$ and $\frac{1}{2}$ .

$2 (\frac{h b}{2} + \frac{h}{2} c) = 2 a$

Combine $\frac{h}{2}$ and $c$ .

$2 (\frac{h b}{2} + \frac{h c}{2}) = 2 a$

Apply the distributive property.

$2 \frac{h b}{2} + 2 \frac{h c}{2} = 2 a$

Cancel the common factor of $2$ .

Cancel the common factor.

$2 \frac{h b}{2} + 2 \frac{h c}{2} = 2 a$

Rewrite the expression.

$h b + 2 \frac{h c}{2} = 2 a$

Cancel the common factor of $2$ .

Cancel the common factor.

$h b + 2 \frac{h c}{2} = 2 a$

Rewrite the expression.

$h b + h c = 2 a$

Step 4

Factor $h$ out of $h b + h c$ .

Factor $h$ out of $h b$ .

$h (b) + h c = 2 a$

Factor $h$ out of $h c$ .

$h (b) + h (c) = 2 a$

Factor $h$ out of $h (b) + h (c)$ .

$h (b + c) = 2 a$

Step 5

Divide each term in $h (b + c) = 2 a$ by $b + c$ and simplify.

Divide each term in $h (b + c) = 2 a$ by $b + c$ .

$\frac{h (b + c)}{b + c} = \frac{2 a}{b + c}$

Simplify the left side.

Cancel the common factor of $b + c$ .

Cancel the common factor.

$\frac{h (b + c)}{b + c} = \frac{2 a}{b + c}$

Divide $h$ by $1$ .

$h = \frac{2 a}{b + c}$

Solve for h a=1/2*(h(b+c))

Related Questions

Support LCMGCF.com by disabling your adblocker.