Solve for h A=1/2h(b+B)

$A = \frac{1}{2} h (b + B)$

Step 1

Rewrite the equation as $\frac{1}{2} \cdot (h (b + B)) = A$ .

$\frac{1}{2} \cdot (h (b + B)) = A$

Step 2

Multiply both sides of the equation by $2$ .

$2 (\frac{1}{2} \cdot (h (b + B))) = 2 A$

Step 3

Simplify the left side.

Simplify $2 (\frac{1}{2} \cdot (h (b + B)))$ .

Apply the distributive property.

$2 (\frac{1}{2} \cdot (h b + h B)) = 2 A$

Apply the distributive property.

$2 (\frac{1}{2} (h b) + \frac{1}{2} (h B)) = 2 A$

Multiply $\frac{1}{2} (h b)$ .

Combine $h$ and $\frac{1}{2}$ .

$2 (\frac{h}{2} b + \frac{1}{2} (h B)) = 2 A$

Combine $\frac{h}{2}$ and $b$ .

$2 (\frac{h b}{2} + \frac{1}{2} (h B)) = 2 A$

Multiply $\frac{1}{2} (h B)$ .

Combine $h$ and $\frac{1}{2}$ .

$2 (\frac{h b}{2} + \frac{h}{2} B) = 2 A$

Combine $\frac{h}{2}$ and $B$ .

$2 (\frac{h b}{2} + \frac{h B}{2}) = 2 A$

Apply the distributive property.

$2 \frac{h b}{2} + 2 \frac{h B}{2} = 2 A$

Cancel the common factor of $2$ .

Cancel the common factor.

$2 \frac{h b}{2} + 2 \frac{h B}{2} = 2 A$

Rewrite the expression.

$h b + 2 \frac{h B}{2} = 2 A$

Cancel the common factor of $2$ .

Cancel the common factor.

$h b + 2 \frac{h B}{2} = 2 A$

Rewrite the expression.

$h b + h B = 2 A$

Step 4

Factor $h$ out of $h b + h B$ .

Factor $h$ out of $h b$ .

$h (b) + h B = 2 A$

Factor $h$ out of $h B$ .

$h (b) + h (B) = 2 A$

Factor $h$ out of $h (b) + h (B)$ .

$h (b + B) = 2 A$

Step 5

Divide each term in $h (b + B) = 2 A$ by $b + B$ and simplify.

Divide each term in $h (b + B) = 2 A$ by $b + B$ .

$\frac{h (b + B)}{b + B} = \frac{2 A}{b + B}$

Simplify the left side.

Cancel the common factor of $b + B$ .

Cancel the common factor.

$\frac{h (b + B)}{b + B} = \frac{2 A}{b + B}$

Divide $h$ by $1$ .

$h = \frac{2 A}{b + B}$

Solve for h A=1/2h(b+B)

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