Solve for h (h-1)(5h+4)=0

$(h - 1) (5 h + 4) = 0$

Step 1

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$h - 1 = 0$

$5 h + 4 = 0$

Step 2

Set $h - 1$ equal to $0$ and solve for $h$ .

Set $h - 1$ equal to $0$ .

$h - 1 = 0$

Add $1$ to both sides of the equation.

$h = 1$

Step 3

Set $5 h + 4$ equal to $0$ and solve for $h$ .

Set $5 h + 4$ equal to $0$ .

$5 h + 4 = 0$

Solve $5 h + 4 = 0$ for $h$ .

Subtract $4$ from both sides of the equation.

$5 h = - 4$

Divide each term in $5 h = - 4$ by $5$ and simplify.

Divide each term in $5 h = - 4$ by $5$ .

$\frac{5 h}{5} = \frac{- 4}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 h}{5} = \frac{- 4}{5}$

Divide $h$ by $1$ .

$h = \frac{- 4}{5}$

Simplify the right side.

Move the negative in front of the fraction.

$h = - \frac{4}{5}$

Step 4

The final solution is all the values that make $(h - 1) (5 h + 4) = 0$ true.

$h = 1, - \frac{4}{5}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$h = 1, - \frac{4}{5}$

Decimal Form:

$h = 1, - 0.8$