Solve for h -h/3-4=13

$- \frac{h}{3} - 4 = 13$

Move all terms not containing $h$ to the right side of the equation.

Add $4$ to both sides of the equation.

$- \frac{h}{3} = 13 + 4$

Add $13$ and $4$ .

$- \frac{h}{3} = 17$

Multiply both sides of the equation by $- 3$ .

$- 3 (- \frac{h}{3}) = - 3 \cdot 17$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 3 (- \frac{h}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{h}{3}$ into the numerator.

$- 3 \frac{- h}{3} = - 3 \cdot 17$

Factor $3$ out of $- 3$ .

$3 (- 1) \frac{- h}{3} = - 3 \cdot 17$

Cancel the common factor.

$3 \cdot - 1 \frac{- h}{3} = - 3 \cdot 17$

Rewrite the expression.

$- - h = - 3 \cdot 17$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 h = - 3 \cdot 17$

Multiply $h$ by $1$ .

$h = - 3 \cdot 17$

Simplify the right side.

Multiply $- 3$ by $17$ .

$h = - 51$