Solve for H3 3.5=- log of H_3O

$3.5 = - \log (H_{3} O)$

Step 1

Since $H_{3}$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- \log (H_{3} O) = 3.5$

Step 2

Add $\log (H_{3} O)$ to both sides of the equation.

$0 = 3.5 + \log (H_{3} O)$

Step 3

Rewrite the equation as $3.5 + \log (H_{3} O) = 0$ .

$3.5 + \log (H_{3} O) = 0$