Solve for I 6.2 = log of I/1

Rewrite the equation as ${\displaystyle \log \left(\frac{I}{1}\right)=6.2}$.

Rewrite ${\displaystyle \log \left(\frac{I}{1}\right)=6.2}$ in exponential form using the definition of a logarithm. If ${\displaystyle x}$ and ${\displaystyle b}$ are positive real numbers and ${\displaystyle b\ne 1}$, then ${\displaystyle {\log }_b\left(x\right)=y}$ is equivalent to ${\displaystyle b^y=x}$.