Solve for I0 D=10 log of I/I_0

$D = 10 \log (\frac{I}{I_{0}})$

Step 1

Simplify $10 \log (\frac{I}{I_{0}})$ by moving $10$ inside the logarithm.

$D = \log ({(\frac{I}{I_{0}})}^{10})$

Step 2

Apply the product rule to $\frac{I}{I_{0}}$ .

$D = \log (\frac{I^{10}}{{I_{0}}^{10}})$