Solve for j -1/3=j/4-10/3

$- \frac{1}{3} = \frac{j}{4} - \frac{10}{3}$

Rewrite the equation as $\frac{j}{4} - \frac{10}{3} = - \frac{1}{3}$ .

$\frac{j}{4} - \frac{10}{3} = - \frac{1}{3}$

Move all terms not containing $j$ to the right side of the equation.

Add $\frac{10}{3}$ to both sides of the equation.

$\frac{j}{4} = - \frac{1}{3} + \frac{10}{3}$

Combine the numerators over the common denominator.

$\frac{j}{4} = \frac{- 1 + 10}{3}$

Add $- 1$ and $10$ .

$\frac{j}{4} = \frac{9}{3}$

Divide $9$ by $3$ .

$\frac{j}{4} = 3$

Multiply both sides of the equation by $4$ .

$4 \frac{j}{4} = 4 \cdot 3$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$4 \frac{j}{4} = 4 \cdot 3$

Rewrite the expression.

$j = 4 \cdot 3$

Simplify the right side.

Multiply $4$ by $3$ .

$j = 12$