Solve for j 3(2j-k)=108

$3 (2 j - k) = 108$

Divide each term in $3 (2 j - k) = 108$ by $3$ and simplify.

Divide each term in $3 (2 j - k) = 108$ by $3$ .

$\frac{3 (2 j - k)}{3} = \frac{108}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (2 j - k)}{3} = \frac{108}{3}$

Divide $2 j - k$ by $1$ .

$2 j - k = \frac{108}{3}$

Simplify the right side.

Divide $108$ by $3$ .

$2 j - k = 36$

Add $k$ to both sides of the equation.

$2 j = 36 + k$

Divide each term in $2 j = 36 + k$ by $2$ and simplify.

Divide each term in $2 j = 36 + k$ by $2$ .

$\frac{2 j}{2} = \frac{36}{2} + \frac{k}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 j}{2} = \frac{36}{2} + \frac{k}{2}$

Divide $j$ by $1$ .

$j = \frac{36}{2} + \frac{k}{2}$

Simplify the right side.

Divide $36$ by $2$ .

$j = 18 + \frac{k}{2}$