Solve for j 3(-6j-2)=-13-11j-6j

$3 (- 6 j - 2) = - 13 - 11 j - 6 j$

Since $j$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- 13 - 11 j - 6 j = 3 (- 6 j - 2)$

Subtract $6 j$ from $- 11 j$ .

$- 13 - 17 j = 3 (- 6 j - 2)$

Simplify $3 (- 6 j - 2)$ .

Apply the distributive property.

$- 13 - 17 j = 3 (- 6 j) + 3 \cdot - 2$

Multiply.

Multiply $- 6$ by $3$ .

$- 13 - 17 j = - 18 j + 3 \cdot - 2$

Multiply $3$ by $- 2$ .

$- 13 - 17 j = - 18 j - 6$

Move all terms containing $j$ to the left side of the equation.

Add $18 j$ to both sides of the equation.

$- 13 - 17 j + 18 j = - 6$

Add $- 17 j$ and $18 j$ .

$- 13 + j = - 6$

Move all terms not containing $j$ to the right side of the equation.

Add $13$ to both sides of the equation.

$j = - 6 + 13$

Add $- 6$ and $13$ .

$j = 7$