Solve for j 6(j-10)=-8j+10

$6 (j - 10) = - 8 j + 10$

Simplify $6 (j - 10)$ .

Rewrite.

$0 + 0 + 6 (j - 10) = - 8 j + 10$

Simplify by adding zeros.

$6 (j - 10) = - 8 j + 10$

Apply the distributive property.

$6 j + 6 \cdot - 10 = - 8 j + 10$

Multiply $6$ by $- 10$ .

$6 j - 60 = - 8 j + 10$

Move all terms containing $j$ to the left side of the equation.

Add $8 j$ to both sides of the equation.

$6 j - 60 + 8 j = 10$

Add $6 j$ and $8 j$ .

$14 j - 60 = 10$

Move all terms not containing $j$ to the right side of the equation.

Add $60$ to both sides of the equation.

$14 j = 10 + 60$

Add $10$ and $60$ .

$14 j = 70$

Divide each term in $14 j = 70$ by $14$ and simplify.

Divide each term in $14 j = 70$ by $14$ .

$\frac{14 j}{14} = \frac{70}{14}$

Simplify the left side.

Cancel the common factor of $14$ .

Cancel the common factor.

$\frac{14 j}{14} = \frac{70}{14}$

Divide $j$ by $1$ .

$j = \frac{70}{14}$

Simplify the right side.

Divide $70$ by $14$ .

$j = 5$