Solve for j 9j-6+6j>=3(5j-2)

$9 j - 6 + 6 j \geq 3 (5 j - 2)$

Add $9 j$ and $6 j$ .

$15 j - 6 \geq 3 (5 j - 2)$

Simplify $3 (5 j - 2)$ .

Apply the distributive property.

$15 j - 6 \geq 3 (5 j) + 3 \cdot - 2$

Multiply.

Multiply $5$ by $3$ .

$15 j - 6 \geq 15 j + 3 \cdot - 2$

Multiply $3$ by $- 2$ .

$15 j - 6 \geq 15 j - 6$

Move all terms containing $j$ to the left side of the inequality.

Subtract $15 j$ from both sides of the inequality.

$15 j - 6 - 15 j \geq - 6$

Combine the opposite terms in $15 j - 6 - 15 j$ .

Subtract $15 j$ from $15 j$ .

$0 - 6 \geq - 6$

Subtract $6$ from $0$ .

$- 6 \geq - 6$

Since $- 6 = - 6$ , the equation will always be true for any value of $j$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$