Solve for j j+10>=-3j-2

$j + 10 \geq - 3 j - 2$

Step 1

Move all terms containing $j$ to the left side of the inequality.

Add $3 j$ to both sides of the inequality.

$j + 10 + 3 j \geq - 2$

Add $j$ and $3 j$ .

$4 j + 10 \geq - 2$

Step 2

Move all terms not containing $j$ to the right side of the inequality.

Subtract $10$ from both sides of the inequality.

$4 j \geq - 2 - 10$

Subtract $10$ from $- 2$ .

$4 j \geq - 12$

Step 3

Divide each term in $4 j \geq - 12$ by $4$ and simplify.

Divide each term in $4 j \geq - 12$ by $4$ .

$\frac{4 j}{4} \geq \frac{- 12}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 j}{4} \geq \frac{- 12}{4}$

Divide $j$ by $1$ .

$j \geq \frac{- 12}{4}$

Simplify the right side.

Divide $- 12$ by $4$ .

$j \geq - 3$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$j \geq - 3$

Interval Notation:

$[- 3, \infty)$