Solve for k 10k-10=5(3k+5)

$10 k - 10 = 5 (3 k + 5)$

Step 1

Simplify $5 (3 k + 5)$ .

Rewrite.

$10 k - 10 = 0 + 0 + 5 (3 k + 5)$

Simplify by adding zeros.

$10 k - 10 = 5 (3 k + 5)$

Apply the distributive property.

$10 k - 10 = 5 (3 k) + 5 \cdot 5$

Multiply.

Multiply $3$ by $5$ .

$10 k - 10 = 15 k + 5 \cdot 5$

Multiply $5$ by $5$ .

$10 k - 10 = 15 k + 25$

Step 2

Move all terms containing $k$ to the left side of the equation.

Subtract $15 k$ from both sides of the equation.

$10 k - 10 - 15 k = 25$

Subtract $15 k$ from $10 k$ .

$- 5 k - 10 = 25$

Step 3

Move all terms not containing $k$ to the right side of the equation.

Add $10$ to both sides of the equation.

$- 5 k = 25 + 10$

Add $25$ and $10$ .

$- 5 k = 35$

Step 4

Divide each term in $- 5 k = 35$ by $- 5$ and simplify.

Divide each term in $- 5 k = 35$ by $- 5$ .

$\frac{- 5 k}{- 5} = \frac{35}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 k}{- 5} = \frac{35}{- 5}$

Divide $k$ by $1$ .

$k = \frac{35}{- 5}$

Simplify the right side.

Divide $35$ by $- 5$ .

$k = - 7$