Solve for k 12(2k+11)=12(2k+12)

$12 (2 k + 11) = 12 (2 k + 12)$

Step 1

Simplify $12 (2 k + 11)$ .

Rewrite.

$0 + 0 + 12 (2 k + 11) = 12 (2 k + 12)$

Simplify by adding zeros.

$12 (2 k + 11) = 12 (2 k + 12)$

Apply the distributive property.

$12 (2 k) + 12 \cdot 11 = 12 (2 k + 12)$

Multiply.

Multiply $2$ by $12$ .

$24 k + 12 \cdot 11 = 12 (2 k + 12)$

Multiply $12$ by $11$ .

$24 k + 132 = 12 (2 k + 12)$

Step 2

Simplify $12 (2 k + 12)$ .

Apply the distributive property.

$24 k + 132 = 12 (2 k) + 12 \cdot 12$

Multiply.

Multiply $2$ by $12$ .

$24 k + 132 = 24 k + 12 \cdot 12$

Multiply $12$ by $12$ .

$24 k + 132 = 24 k + 144$

Step 3

Move all terms containing $k$ to the left side of the equation.

Subtract $24 k$ from both sides of the equation.

$24 k + 132 - 24 k = 144$

Combine the opposite terms in $24 k + 132 - 24 k$ .

Subtract $24 k$ from $24 k$ .

$0 + 132 = 144$

Add $0$ and $132$ .

$132 = 144$

Step 4

Since $132 \neq 144$ , there are no solutions.

No solution