Solve for k 13-19k=-10+9(-k-13)

$13 - 19 k = - 10 + 9 (- k - 13)$

Step 1

Simplify $- 10 + 9 (- k - 13)$ .

Simplify each term.

Apply the distributive property.

$13 - 19 k = - 10 + 9 (- k) + 9 \cdot - 13$

Multiply $- 1$ by $9$ .

$13 - 19 k = - 10 - 9 k + 9 \cdot - 13$

Multiply $9$ by $- 13$ .

$13 - 19 k = - 10 - 9 k - 117$

Subtract $117$ from $- 10$ .

$13 - 19 k = - 9 k - 127$

Step 2

Move all terms containing $k$ to the left side of the equation.

Add $9 k$ to both sides of the equation.

$13 - 19 k + 9 k = - 127$

Add $- 19 k$ and $9 k$ .

$13 - 10 k = - 127$

Step 3

Move all terms not containing $k$ to the right side of the equation.

Subtract $13$ from both sides of the equation.

$- 10 k = - 127 - 13$

Subtract $13$ from $- 127$ .

$- 10 k = - 140$

Step 4

Divide each term in $- 10 k = - 140$ by $- 10$ and simplify.

Divide each term in $- 10 k = - 140$ by $- 10$ .

$\frac{- 10 k}{- 10} = \frac{- 140}{- 10}$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 k}{- 10} = \frac{- 140}{- 10}$

Divide $k$ by $1$ .

$k = \frac{- 140}{- 10}$

Simplify the right side.

Divide $- 140$ by $- 10$ .

$k = 14$