Solve for k -18-6k=6(1+3k)

$- 18 - 6 k = 6 (1 + 3 k)$

Step 1

Simplify $6 (1 + 3 k)$ .

Rewrite.

$- 18 - 6 k = 0 + 0 + 6 (1 + 3 k)$

Simplify by adding zeros.

$- 18 - 6 k = 6 (1 + 3 k)$

Apply the distributive property.

$- 18 - 6 k = 6 \cdot 1 + 6 (3 k)$

Multiply.

Multiply $6$ by $1$ .

$- 18 - 6 k = 6 + 6 (3 k)$

Multiply $3$ by $6$ .

$- 18 - 6 k = 6 + 18 k$

Step 2

Move all terms containing $k$ to the left side of the equation.

Subtract $18 k$ from both sides of the equation.

$- 18 - 6 k - 18 k = 6$

Subtract $18 k$ from $- 6 k$ .

$- 18 - 24 k = 6$

Step 3

Move all terms not containing $k$ to the right side of the equation.

Add $18$ to both sides of the equation.

$- 24 k = 6 + 18$

Add $6$ and $18$ .

$- 24 k = 24$

Step 4

Divide each term in $- 24 k = 24$ by $- 24$ and simplify.

Divide each term in $- 24 k = 24$ by $- 24$ .

$\frac{- 24 k}{- 24} = \frac{24}{- 24}$

Simplify the left side.

Cancel the common factor of $- 24$ .

Cancel the common factor.

$\frac{- 24 k}{- 24} = \frac{24}{- 24}$

Divide $k$ by $1$ .

$k = \frac{24}{- 24}$

Simplify the right side.

Divide $24$ by $- 24$ .

$k = - 1$