Solve for k 28=-k+16-2k-9

$28 = - k + 16 - 2 k - 9$

Step 1

Rewrite the equation as $- k + 16 - 2 k - 9 = 28$ .

$- k + 16 - 2 k - 9 = 28$

Step 2

Simplify $- k + 16 - 2 k - 9$ .

Subtract $2 k$ from $- k$ .

$- 3 k + 16 - 9 = 28$

Subtract $9$ from $16$ .

$- 3 k + 7 = 28$

Step 3

Move all terms not containing $k$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- 3 k = 28 - 7$

Subtract $7$ from $28$ .

$- 3 k = 21$

Step 4

Divide each term in $- 3 k = 21$ by $- 3$ and simplify.

Divide each term in $- 3 k = 21$ by $- 3$ .

$\frac{- 3 k}{- 3} = \frac{21}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 k}{- 3} = \frac{21}{- 3}$

Divide $k$ by $1$ .

$k = \frac{21}{- 3}$

Simplify the right side.

Divide $21$ by $- 3$ .

$k = - 7$