Solve for k 28-k>=7(k-4)

$28 - k \geq 7 (k - 4)$

Simplify $7 (k - 4)$ .

Rewrite.

$28 - k \geq 0 + 0 + 7 (k - 4)$

Simplify by adding zeros.

$28 - k \geq 7 (k - 4)$

Apply the distributive property.

$28 - k \geq 7 k + 7 \cdot - 4$

Multiply $7$ by $- 4$ .

$28 - k \geq 7 k - 28$

Move all terms containing $k$ to the left side of the inequality.

Subtract $7 k$ from both sides of the inequality.

$28 - k - 7 k \geq - 28$

Subtract $7 k$ from $- k$ .

$28 - 8 k \geq - 28$

Move all terms not containing $k$ to the right side of the inequality.

Subtract $28$ from both sides of the inequality.

$- 8 k \geq - 28 - 28$

Subtract $28$ from $- 28$ .

$- 8 k \geq - 56$

Divide each term in $- 8 k \geq - 56$ by $- 8$ and simplify.

Divide each term in $- 8 k \geq - 56$ by $- 8$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 8 k}{- 8} \leq \frac{- 56}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 k}{- 8} \leq \frac{- 56}{- 8}$

Divide $k$ by $1$ .

$k \leq \frac{- 56}{- 8}$

Simplify the right side.

Divide $- 56$ by $- 8$ .

$k \leq 7$

The result can be shown in multiple forms.

Inequality Form:

$k \leq 7$

Interval Notation:

$(- \infty, 7]$

Solve for k 28-k>=7(k-4)

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