Solve for k 3(k-5)=-16

$3 (k - 5) = - 16$

Step 1

Divide each term in $3 (k - 5) = - 16$ by $3$ and simplify.

Divide each term in $3 (k - 5) = - 16$ by $3$ .

$\frac{3 (k - 5)}{3} = \frac{- 16}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (k - 5)}{3} = \frac{- 16}{3}$

Divide $k - 5$ by $1$ .

$k - 5 = \frac{- 16}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$k - 5 = - \frac{16}{3}$

Step 2

Move all terms not containing $k$ to the right side of the equation.

Add $5$ to both sides of the equation.

$k = - \frac{16}{3} + 5$

To write $5$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$k = - \frac{16}{3} + 5 \cdot \frac{3}{3}$

Combine $5$ and $\frac{3}{3}$ .

$k = - \frac{16}{3} + \frac{5 \cdot 3}{3}$

Combine the numerators over the common denominator.

$k = \frac{- 16 + 5 \cdot 3}{3}$

Simplify the numerator.

Multiply $5$ by $3$ .

$k = \frac{- 16 + 15}{3}$

Add $- 16$ and $15$ .

$k = \frac{- 1}{3}$

Move the negative in front of the fraction.

$k = - \frac{1}{3}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$k = - \frac{1}{3}$

Decimal Form:

$k = - 0.\overline{3}$