Solve for k 310-(307)=5k

$310 - (30 \times 7) = 5 \times k$

Step 1

Rewrite the equation as $5 \cdot k = 310 - 1 \cdot 30 \cdot 7$ .

$5 \cdot k = 310 - 1 \cdot 30 \cdot 7$

Step 2

Simplify.

Multiply $- 1$ by $30$ .

$5 \cdot k = 310 - 30 \cdot 7$

Multiply $- 30$ by $7$ .

$5 \cdot k = 310 - 210$

Subtract $210$ from $310$ .

$5 \cdot k = 100$

Step 3

Divide each term in $(5 \cdot k) = 100$ by $5$ and simplify.

Divide each term in $(5 \cdot k) = 100$ by $5$ .

$\frac{(5 \cdot k)}{5} = \frac{100}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 \cdot k}{5} = \frac{100}{5}$

Divide $k$ by $1$ .

$k = \frac{100}{5}$

Simplify the right side.

Divide $100$ by $5$ .

$k = 20$

Solve for k 310-(30*7)=5*k