Solve for k 3k-14=3(k-5)+1

$3 k - 14 = 3 (k - 5) + 1$

Step 1

Simplify $3 (k - 5) + 1$ .

Simplify each term.

Apply the distributive property.

$3 k - 14 = 3 k + 3 \cdot - 5 + 1$

Multiply $3$ by $- 5$ .

$3 k - 14 = 3 k - 15 + 1$

Add $- 15$ and $1$ .

$3 k - 14 = 3 k - 14$

Step 2

Move all terms containing $k$ to the left side of the equation.

Subtract $3 k$ from both sides of the equation.

$3 k - 14 - 3 k = - 14$

Combine the opposite terms in $3 k - 14 - 3 k$ .

Subtract $3 k$ from $3 k$ .

$0 - 14 = - 14$

Subtract $14$ from $0$ .

$- 14 = - 14$

Step 3

Since $- 14 = - 14$ , the equation will always be true for any value of $k$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$