Solve for k -4|7-6k|=14

$- 4 | 7 - 6 k | = 14$

Divide each term in $- 4 | 7 - 6 k | = 14$ by $- 4$ and simplify.

Divide each term in $- 4 | 7 - 6 k | = 14$ by $- 4$ .

$\frac{- 4 | 7 - 6 k |}{- 4} = \frac{14}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 | 7 - 6 k |}{- 4} = \frac{14}{- 4}$

Divide $| 7 - 6 k |$ by $1$ .

$| 7 - 6 k | = \frac{14}{- 4}$

Simplify the right side.

Cancel the common factor of $14$ and $- 4$ .

Factor $2$ out of $14$ .

$| 7 - 6 k | = \frac{2 (7)}{- 4}$

Cancel the common factors.

Factor $2$ out of $- 4$ .

$| 7 - 6 k | = \frac{2 \cdot 7}{2 \cdot - 2}$

Cancel the common factor.

$| 7 - 6 k | = \frac{2 \cdot 7}{2 \cdot - 2}$

Rewrite the expression.

$| 7 - 6 k | = \frac{7}{- 2}$

Move the negative in front of the fraction.

$| 7 - 6 k | = - \frac{7}{2}$

There is no value of $k$ that makes the equation be true since an absolute value can never be negative.

No solution