Solve for k -4k+2(5k-6)=-3k-39

$- 4 k + 2 (5 k - 6) = - 3 k - 39$

Step 1

Simplify $- 4 k + 2 (5 k - 6)$ .

Simplify each term.

Apply the distributive property.

$- 4 k + 2 (5 k) + 2 \cdot - 6 = - 3 k - 39$

Multiply $5$ by $2$ .

$- 4 k + 10 k + 2 \cdot - 6 = - 3 k - 39$

Multiply $2$ by $- 6$ .

$- 4 k + 10 k - 12 = - 3 k - 39$

Add $- 4 k$ and $10 k$ .

$6 k - 12 = - 3 k - 39$

Step 2

Move all terms containing $k$ to the left side of the equation.

Add $3 k$ to both sides of the equation.

$6 k - 12 + 3 k = - 39$

Add $6 k$ and $3 k$ .

$9 k - 12 = - 39$

Step 3

Move all terms not containing $k$ to the right side of the equation.

Add $12$ to both sides of the equation.

$9 k = - 39 + 12$

Add $- 39$ and $12$ .

$9 k = - 27$

Step 4

Divide each term in $9 k = - 27$ by $9$ and simplify.

Divide each term in $9 k = - 27$ by $9$ .

$\frac{9 k}{9} = \frac{- 27}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 k}{9} = \frac{- 27}{9}$

Divide $k$ by $1$ .

$k = \frac{- 27}{9}$

Simplify the right side.

Divide $- 27$ by $9$ .

$k = - 3$