Solve for k 5k-9-2k+3=3k-6

$5 k - 9 - 2 k + 3 = 3 k - 6$

Step 1

Simplify $5 k - 9 - 2 k + 3$ .

Subtract $2 k$ from $5 k$ .

$3 k - 9 + 3 = 3 k - 6$

Add $- 9$ and $3$ .

$3 k - 6 = 3 k - 6$

Step 2

Move all terms containing $k$ to the left side of the equation.

Subtract $3 k$ from both sides of the equation.

$3 k - 6 - 3 k = - 6$

Combine the opposite terms in $3 k - 6 - 3 k$ .

Subtract $3 k$ from $3 k$ .

$0 - 6 = - 6$

Subtract $6$ from $0$ .

$- 6 = - 6$

Step 3

Since $- 6 = - 6$ , the equation will always be true for any value of $k$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$