Solve for k -6(1+7k)+7(1+6k)=-2

$- 6 (1 + 7 k) + 7 (1 + 6 k) = - 2$

Step 1

Simplify $- 6 (1 + 7 k) + 7 (1 + 6 k)$ .

Simplify each term.

Apply the distributive property.

$- 6 \cdot 1 - 6 (7 k) + 7 (1 + 6 k) = - 2$

Multiply $- 6$ by $1$ .

$- 6 - 6 (7 k) + 7 (1 + 6 k) = - 2$

Multiply $7$ by $- 6$ .

$- 6 - 42 k + 7 (1 + 6 k) = - 2$

Apply the distributive property.

$- 6 - 42 k + 7 \cdot 1 + 7 (6 k) = - 2$

Multiply $7$ by $1$ .

$- 6 - 42 k + 7 + 7 (6 k) = - 2$

Multiply $6$ by $7$ .

$- 6 - 42 k + 7 + 42 k = - 2$

Simplify by adding terms.

Combine the opposite terms in $- 6 - 42 k + 7 + 42 k$ .

Add $- 42 k$ and $42 k$ .

$- 6 + 0 + 7 = - 2$

Add $- 6$ and $0$ .

$- 6 + 7 = - 2$

Add $- 6$ and $7$ .

$1 = - 2$

Step 2

Since $1 \neq - 2$ , there are no solutions.

No solution