Solve for k 8(3/4k+3)=8-2k

$8 (\frac{3}{4} k + 3) = 8 - 2 k$

Simplify $8 (\frac{3}{4} k + 3)$ .

Rewrite.

$0 + 0 + 8 (\frac{3}{4} k + 3) = 8 - 2 k$

Simplify by adding zeros.

$8 (\frac{3}{4} k + 3) = 8 - 2 k$

Combine $\frac{3}{4}$ and $k$ .

$8 (\frac{3 k}{4} + 3) = 8 - 2 k$

Apply the distributive property.

$8 \frac{3 k}{4} + 8 \cdot 3 = 8 - 2 k$

Cancel the common factor of $4$ .

Factor $4$ out of $8$ .

$4 (2) \frac{3 k}{4} + 8 \cdot 3 = 8 - 2 k$

Cancel the common factor.

$4 \cdot 2 \frac{3 k}{4} + 8 \cdot 3 = 8 - 2 k$

Rewrite the expression.

$2 (3 k) + 8 \cdot 3 = 8 - 2 k$

Multiply.

Multiply $3$ by $2$ .

$6 k + 8 \cdot 3 = 8 - 2 k$

Multiply $8$ by $3$ .

$6 k + 24 = 8 - 2 k$

Move all terms containing $k$ to the left side of the equation.

Add $2 k$ to both sides of the equation.

$6 k + 24 + 2 k = 8$

Add $6 k$ and $2 k$ .

$8 k + 24 = 8$

Move all terms not containing $k$ to the right side of the equation.

Subtract $24$ from both sides of the equation.

$8 k = 8 - 24$

Subtract $24$ from $8$ .

$8 k = - 16$

Divide each term in $8 k = - 16$ by $8$ and simplify.

Divide each term in $8 k = - 16$ by $8$ .

$\frac{8 k}{8} = \frac{- 16}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 k}{8} = \frac{- 16}{8}$

Divide $k$ by $1$ .

$k = \frac{- 16}{8}$

Simplify the right side.

Divide $- 16$ by $8$ .

$k = - 2$