Solve for k 8-3(k+2)=2-3k

$8 - 3 (k + 2) = 2 - 3 k$

Step 1

Simplify $8 - 3 (k + 2)$ .

Simplify each term.

Apply the distributive property.

$8 - 3 k - 3 \cdot 2 = 2 - 3 k$

Multiply $- 3$ by $2$ .

$8 - 3 k - 6 = 2 - 3 k$

Subtract $6$ from $8$ .

$- 3 k + 2 = 2 - 3 k$

Step 2

Move all terms containing $k$ to the left side of the equation.

Add $3 k$ to both sides of the equation.

$- 3 k + 2 + 3 k = 2$

Combine the opposite terms in $- 3 k + 2 + 3 k$ .

Add $- 3 k$ and $3 k$ .

$0 + 2 = 2$

Add $0$ and $2$ .

$2 = 2$

Step 3

Since $2 = 2$ , the equation will always be true for any value of $k$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$