Solve for k 8+k<=-3

$8 + k \leq - 3$

Subtract $8$ from both sides of the inequality.

$k \leq - 3 - 8$

Subtract $8$ from $- 3$ .

$k \leq - 11$

The result can be shown in multiple forms.

Inequality Form:

$k \leq - 11$

Interval Notation:

$(- \infty, - 11]$

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