Solve for k x=(4-k)/6

$x = \frac{4 - k}{6}$

Step 1

Rewrite the equation as $\frac{4 - k}{6} = x$ .

$\frac{4 - k}{6} = x$

Step 2

Multiply both sides by $6$ .

$\frac{4 - k}{6} \cdot 6 = x \cdot 6$

Step 3

Simplify.

Simplify the left side.

Simplify $\frac{4 - k}{6} \cdot 6$ .

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{4 - k}{6} \cdot 6 = x \cdot 6$

Rewrite the expression.

$4 - k = x \cdot 6$

Reorder $4$ and $- k$ .

$- k + 4 = x \cdot 6$

Simplify the right side.

Move $6$ to the left of $x$ .

$- k + 4 = 6 x$

Step 4

Solve for $k$ .

Subtract $4$ from both sides of the equation.

$- k = 6 x - 4$

Divide each term in $- k = 6 x - 4$ by $- 1$ and simplify.

Divide each term in $- k = 6 x - 4$ by $- 1$ .

$\frac{- k}{- 1} = \frac{6 x}{- 1} + \frac{- 4}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{k}{1} = \frac{6 x}{- 1} + \frac{- 4}{- 1}$

Divide $k$ by $1$ .

$k = \frac{6 x}{- 1} + \frac{- 4}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{6 x}{- 1}$ .

$k = - 1 \cdot (6 x) + \frac{- 4}{- 1}$

Rewrite $- 1 \cdot (6 x)$ as $- (6 x)$ .

$k = - (6 x) + \frac{- 4}{- 1}$

Multiply $6$ by $- 1$ .

$k = - 6 x + \frac{- 4}{- 1}$

Divide $- 4$ by $- 1$ .

$k = - 6 x + 4$