Solve for k x(4-k)=p

$x (4 - k) = p$

Step 1

Divide each term in $x (4 - k) = p$ by $x$ and simplify.

Divide each term in $x (4 - k) = p$ by $x$ .

$\frac{x (4 - k)}{x} = \frac{p}{x}$

Simplify the left side.

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{x (4 - k)}{x} = \frac{p}{x}$

Divide $4 - k$ by $1$ .

$4 - k = \frac{p}{x}$

Step 2

Subtract $4$ from both sides of the equation.

$- k = \frac{p}{x} - 4$

Step 3

Divide each term in $- k = \frac{p}{x} - 4$ by $- 1$ and simplify.

Divide each term in $- k = \frac{p}{x} - 4$ by $- 1$ .

$\frac{- k}{- 1} = \frac{\frac{p}{x}}{- 1} + \frac{- 4}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{k}{1} = \frac{\frac{p}{x}}{- 1} + \frac{- 4}{- 1}$

Divide $k$ by $1$ .

$k = \frac{\frac{p}{x}}{- 1} + \frac{- 4}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{\frac{p}{x}}{- 1}$ .

$k = - 1 \cdot \frac{p}{x} + \frac{- 4}{- 1}$

Rewrite $- 1 \cdot \frac{p}{x}$ as $- \frac{p}{x}$ .

$k = - \frac{p}{x} + \frac{- 4}{- 1}$

Divide $- 4$ by $- 1$ .

$k = - \frac{p}{x} + 4$