Solve for l 3n^3(l+q)=r

$3 n^{3} (l + q) = r$

Step 1

Divide each term in $3 n^{3} (l + q) = r$ by $3 n^{3}$ and simplify.

Divide each term in $3 n^{3} (l + q) = r$ by $3 n^{3}$ .

$\frac{3 n^{3} (l + q)}{3 n^{3}} = \frac{r}{3 n^{3}}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 n^{3} (l + q)}{3 n^{3}} = \frac{r}{3 n^{3}}$

Rewrite the expression.

$\frac{n^{3} (l + q)}{n^{3}} = \frac{r}{3 n^{3}}$

Cancel the common factor of $n^{3}$ .

Cancel the common factor.

$\frac{n^{3} (l + q)}{n^{3}} = \frac{r}{3 n^{3}}$

Divide $l + q$ by $1$ .

$l + q = \frac{r}{3 n^{3}}$

Step 2

Subtract $q$ from both sides of the equation.

$l = \frac{r}{3 n^{3}} - q$