Solve for l nl+4Ql=9

$n l + 4 Q l = 9$

Step 1

Factor $l$ out of $n l + 4 Q l$ .

Factor $l$ out of $n l$ .

$l n + 4 Q l = 9$

Factor $l$ out of $4 Q l$ .

$l n + l (4 Q) = 9$

Factor $l$ out of $l n + l (4 Q)$ .

$l (n + 4 Q) = 9$

Step 2

Divide each term in $l (n + 4 Q) = 9$ by $n + 4 Q$ and simplify.

Divide each term in $l (n + 4 Q) = 9$ by $n + 4 Q$ .

$\frac{l (n + 4 Q)}{n + 4 Q} = \frac{9}{n + 4 Q}$

Simplify the left side.

Cancel the common factor of $n + 4 Q$ .

Cancel the common factor.

$\frac{l (n + 4 Q)}{n + 4 Q} = \frac{9}{n + 4 Q}$

Divide $l$ by $1$ .

$l = \frac{9}{n + 4 Q}$