Solve for l theta=2pi square root of l/g

$θ = 2 π \sqrt{\frac{l}{g}}$

Step 1

Rewrite the equation as $2 π \sqrt{\frac{l}{g}} = θ$ .

$2 π \sqrt{\frac{l}{g}} = θ$

Step 2

To remove the radical on the left side of the equation, square both sides of the equation.

${(2 π \sqrt{\frac{l}{g}})}^{2} = θ^{2}$

Step 3

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{\frac{l}{g}}$ as ${(\frac{l}{g})}^{\frac{1}{2}}$ .

${(2 π {(\frac{l}{g})}^{\frac{1}{2}})}^{2} = θ^{2}$

Simplify the left side.

Simplify ${(2 π {(\frac{l}{g})}^{\frac{1}{2}})}^{2}$ .

Apply the product rule to $\frac{l}{g}$ .

${(2 π \frac{l^{\frac{1}{2}}}{g^{\frac{1}{2}}})}^{2} = θ^{2}$

Multiply $2 π \frac{l^{\frac{1}{2}}}{g^{\frac{1}{2}}}$ .

Combine $\frac{l^{\frac{1}{2}}}{g^{\frac{1}{2}}}$ and $2$ .

${(\frac{l^{\frac{1}{2}} \cdot 2}{g^{\frac{1}{2}}} π)}^{2} = θ^{2}$

Combine $\frac{l^{\frac{1}{2}} \cdot 2}{g^{\frac{1}{2}}}$ and $π$ .

${(\frac{l^{\frac{1}{2}} \cdot 2 π}{g^{\frac{1}{2}}})}^{2} = θ^{2}$

Move $2$ to the left of $l^{\frac{1}{2}}$ .

${(\frac{2 \cdot l^{\frac{1}{2}} π}{g^{\frac{1}{2}}})}^{2} = θ^{2}$

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $\frac{2 l^{\frac{1}{2}} π}{g^{\frac{1}{2}}}$ .

$\frac{{(2 l^{\frac{1}{2}} π)}^{2}}{{(g^{\frac{1}{2}})}^{2}} = θ^{2}$

Apply the product rule to $2 l^{\frac{1}{2}} π$ .

$\frac{{(2 l^{\frac{1}{2}})}^{2} π^{2}}{{(g^{\frac{1}{2}})}^{2}} = θ^{2}$

Apply the product rule to $2 l^{\frac{1}{2}}$ .

$\frac{2^{2} {(l^{\frac{1}{2}})}^{2} π^{2}}{{(g^{\frac{1}{2}})}^{2}} = θ^{2}$

Simplify the numerator.

Raise $2$ to the power of $2$ .

$\frac{4 {(l^{\frac{1}{2}})}^{2} π^{2}}{{(g^{\frac{1}{2}})}^{2}} = θ^{2}$

Multiply the exponents in ${(l^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{4 l^{\frac{1}{2} \cdot 2} π^{2}}{{(g^{\frac{1}{2}})}^{2}} = θ^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{4 l^{\frac{1}{2} \cdot 2} π^{2}}{{(g^{\frac{1}{2}})}^{2}} = θ^{2}$

Rewrite the expression.

$\frac{4 l^{1} π^{2}}{{(g^{\frac{1}{2}})}^{2}} = θ^{2}$

Simplify.

$\frac{4 l π^{2}}{{(g^{\frac{1}{2}})}^{2}} = θ^{2}$

Simplify the denominator.

Multiply the exponents in ${(g^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{4 l π^{2}}{g^{\frac{1}{2} \cdot 2}} = θ^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{4 l π^{2}}{g^{\frac{1}{2} \cdot 2}} = θ^{2}$

Rewrite the expression.

$\frac{4 l π^{2}}{g^{1}} = θ^{2}$

Simplify.

$\frac{4 l π^{2}}{g} = θ^{2}$

Step 4

Solve for $l$ .

Multiply both sides by $g$ .

$\frac{4 l π^{2}}{g} g = θ^{2} g$

Simplify the left side.

Cancel the common factor of $g$ .

Cancel the common factor.

$\frac{4 l π^{2}}{g} g = θ^{2} g$

Rewrite the expression.

$4 l π^{2} = θ^{2} g$

Divide each term in $4 l π^{2} = θ^{2} g$ by $4 π^{2}$ and simplify.

Divide each term in $4 l π^{2} = θ^{2} g$ by $4 π^{2}$ .

$\frac{4 l π^{2}}{4 π^{2}} = \frac{θ^{2} g}{4 π^{2}}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 l π^{2}}{4 π^{2}} = \frac{θ^{2} g}{4 π^{2}}$

Rewrite the expression.

$\frac{l π^{2}}{π^{2}} = \frac{θ^{2} g}{4 π^{2}}$

Cancel the common factor of $π^{2}$ .

Cancel the common factor.

$\frac{l π^{2}}{π^{2}} = \frac{θ^{2} g}{4 π^{2}}$

Divide $l$ by $1$ .

$l = \frac{θ^{2} g}{4 π^{2}}$

Solve for l theta=2pi square root of l/g

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