Solve for m -1/3m+1=-7

$- \frac{1}{3} m + 1 = - 7$

Combine $m$ and $\frac{1}{3}$ .

$- \frac{m}{3} + 1 = - 7$

Move all terms not containing $m$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$- \frac{m}{3} = - 7 - 1$

Subtract $1$ from $- 7$ .

$- \frac{m}{3} = - 8$

Multiply both sides of the equation by $- 3$ .

$- 3 (- \frac{m}{3}) = - 3 \cdot - 8$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 3 (- \frac{m}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{m}{3}$ into the numerator.

$- 3 \frac{- m}{3} = - 3 \cdot - 8$

Factor $3$ out of $- 3$ .

$3 (- 1) \frac{- m}{3} = - 3 \cdot - 8$

Cancel the common factor.

$3 \cdot - 1 \frac{- m}{3} = - 3 \cdot - 8$

Rewrite the expression.

$- - m = - 3 \cdot - 8$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 m = - 3 \cdot - 8$

Multiply $m$ by $1$ .

$m = - 3 \cdot - 8$

Simplify the right side.

Multiply $- 3$ by $- 8$ .

$m = 24$