Solve for m 12m4m=48

$12 m \cdot 4 \cdot m = 48$

Simplify.

Multiply $4$ by $12$ .

$48 m \cdot m = 48$

Raise $m$ to the power of $1$ .

$48 (m^{1} m) = 48$

Raise $m$ to the power of $1$ .

$48 (m^{1} m^{1}) = 48$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$48 m^{1 + 1} = 48$

Add $1$ and $1$ .

$48 m^{2} = 48$

Divide each term in $48 m^{2} = 48$ by $48$ and simplify.

Divide each term in $48 m^{2} = 48$ by $48$ .

$\frac{48 m^{2}}{48} = \frac{48}{48}$

Simplify the left side.

Cancel the common factor of $48$ .

Cancel the common factor.

$\frac{48 m^{2}}{48} = \frac{48}{48}$

Divide $m^{2}$ by $1$ .

$m^{2} = \frac{48}{48}$

Simplify the right side.

Divide $48$ by $48$ .

$m^{2} = 1$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$m = \pm \sqrt{1}$

Any root of $1$ is $1$ .

$m = \pm 1$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$m = 1$

Next, use the negative value of the $\pm$ to find the second solution.

$m = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$m = 1, - 1$

Solve for m 12m*4*m=48