Solve for m -13=5(1+4m)-2m

$- 13 = 5 (1 + 4 m) - 2 m$

Step 1

Rewrite the equation as $5 (1 + 4 m) - 2 m = - 13$ .

$5 (1 + 4 m) - 2 m = - 13$

Step 2

Simplify $5 (1 + 4 m) - 2 m$ .

Simplify each term.

Apply the distributive property.

$5 \cdot 1 + 5 (4 m) - 2 m = - 13$

Multiply $5$ by $1$ .

$5 + 5 (4 m) - 2 m = - 13$

Multiply $4$ by $5$ .

$5 + 20 m - 2 m = - 13$

Subtract $2 m$ from $20 m$ .

$5 + 18 m = - 13$

Step 3

Move all terms not containing $m$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$18 m = - 13 - 5$

Subtract $5$ from $- 13$ .

$18 m = - 18$

Step 4

Divide each term in $18 m = - 18$ by $18$ and simplify.

Divide each term in $18 m = - 18$ by $18$ .

$\frac{18 m}{18} = \frac{- 18}{18}$

Simplify the left side.

Cancel the common factor of $18$ .

Cancel the common factor.

$\frac{18 m}{18} = \frac{- 18}{18}$

Divide $m$ by $1$ .

$m = \frac{- 18}{18}$

Simplify the right side.

Divide $- 18$ by $18$ .

$m = - 1$